Niobium pentaiodide
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(Redirected from Niobium(V) iodide)
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| Other names
Niobium(V) iodide
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| Identifiers | |
| 13779-92-5 | |
| Properties | |
| Nb2I10 | |
| Molar mass | 1475 |
| Appearance | yellow solid |
| Density | 5.30 g/cm3 |
| Melting point | 543 °C (1,009 °F; 816 K) sublimes |
| Vapor pressure | {{{value}}} |
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Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Niobium pentaiodide is the inorganic compound with the formula Nb2I10. It is a yellow, moisture-sensitive, diamagnetic solid. It forms upon heating metallic niobium with iodine.[1] Its structure has been verified by single crystal X-ray diffraction, which reveals an edge-shared bioctahedral structure, as observed for many pentahalides of Nb and Ta. The bonds to the bridging iodides are 0.3 Å longer than the terminal Nb-I bonds.[2]
References
- ↑ G. Brauer "Hydrogen, Deuterium, Water" in Handbook of Preparative Inorganic Chemistry, 2nd Ed. Edited by G. Brauer, Academic Press, 1963, NY. Vol. 2. p. 1315.
- ↑ Krebs, Bernt; Sinram, Diethard "Darstellung, Struktur und Eigenschaften einer neuen Modifikation von NbI5 (Preparation, structure and properties of a new modification of NbI5" Zeitschrift fǔr Naturforschung, Teil B: Anorganische Chemie, Organische Chemie 1980, volume 35b, pp. 12-16.
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- Iodides
- Niobium compounds
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