United States presidential election in Delaware, 1948

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United States presidential election in Delaware, 1948
← 1944 November 2, 1948[1] 1952 →
All 3 Delaware votes to the Electoral College
  ThomasDewey.png Harry S. Truman.jpg
Nominee Thomas Dewey Harry S. Truman
Party Republican Democratic
Home state New York Missouri
Running mate Earl Warren Alben W. Barkley
Electoral vote 3 0
Popular vote 69,588 67,813
Percentage 50.0% 48.8%
President before election

Harry S. Truman
Democratic

 Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Delaware took place on November 2, 1948, as part of the 1948 United States presidential election. Delaware voters chose three[2] representatives, or electors, to the Electoral College, who voted for President and Vice President.

Delaware was won by Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 50.04% of the popular vote, against incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 48.76% of the popular vote.[3][4]

Results

United States presidential election in Delaware, 1948
Party Candidate Votes %
Republican Thomas Dewey 69,588 50.04%
Democratic Harry S. Truman (inc.) 67,813 48.76%
Progressive Henry A. Wallace 1,050 0.75%
Write-in 622 0.45%
Total votes 139,073 100%

References

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