1945 U.S. National Championships – Women's Singles
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Women's Singles | |
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1945 U.S. National Championships | |
Champion | Sarah Palfrey Cooke[1] |
Runner-up | Pauline Betz |
Final score | 3–6, 8–6, 6–4 |
Second-seeded Sarah Palfrey Cooke defeated first-seeded Pauline Betz 3–6, 8–6, 6–4 in the final to win the Women's Singles tennis title at the 1945 U.S. National Championships.[1]
Contents
Seeds
The eight seeded U.S. players are listed below. Sarah Palfrey Cooke is the champion; others show in brackets the round in which they were eliminated.[2][3]
- Pauline Betz (Finalist)
- Sarah Palfrey Cooke (Champion)
- Margaret Osborne (Quarterfinalist)
- Louise Brough (Semifinalist)
- Patricia Todd (Quarterfinalist)
- Mary Arnold (Quarterfinalist)
- Dorothy Bundy (Quarterfinalist)
- Doris Hart (Semifinalist)
One foreign player was seeded.
- Mary Terán de Weiss (Second round)
Draw
Final Eight
Quarterfinals | Semifinals | Finals | |||||||||||||||||
2 | Sarah Palfrey Cooke | 6 | 6 | ||||||||||||||||
7 | Dorothy Bundy | 3 | 4 | ||||||||||||||||
2 | Sarah Palfrey Cooke | 6 | 6 | ||||||||||||||||
4 | Louise Brough | 3 | 4 | ||||||||||||||||
4 | Louise Brough | 6 | 6 | ||||||||||||||||
5 | Patricia Todd | 2 | 4 | ||||||||||||||||
2 | Sarah Palfrey Cooke | 3 | 8 | 6 | |||||||||||||||
1 | Pauline Betz | 6 | 6 | 4 | |||||||||||||||
1 | Pauline Betz | 0 | 6 | 6 | |||||||||||||||
6 | Mary Arnold | 6 | 4 | 4 | |||||||||||||||
1 | Pauline Betz | 6 | 6 | ||||||||||||||||
8 | Doris Hart | 3 | 2 | ||||||||||||||||
3 | Margaret Osborne | 2 | 3 | ||||||||||||||||
8 | Doris Hart | 6 | 6 |