1945 U.S. National Championships – Women's Singles

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Women's Singles
1945 U.S. National Championships
Champion United States Sarah Palfrey Cooke[1]
Runner-up United States Pauline Betz
Final score 3–6, 8–6, 6–4
Events
Singles men women
Doubles men women

Second-seeded Sarah Palfrey Cooke defeated first-seeded Pauline Betz 3–6, 8–6, 6–4 in the final to win the Women's Singles tennis title at the 1945 U.S. National Championships.[1]

Seeds

The eight seeded U.S. players are listed below. Sarah Palfrey Cooke is the champion; others show in brackets the round in which they were eliminated.[2][3]

  1. United States Pauline Betz (Finalist)
  2. United States Sarah Palfrey Cooke (Champion)
  3. United States Margaret Osborne (Quarterfinalist)
  4. United States Louise Brough (Semifinalist)
  5. United States Patricia Todd (Quarterfinalist)
  6. United States Mary Arnold (Quarterfinalist)
  7. United States Dorothy Bundy (Quarterfinalist)
  8. United States Doris Hart (Semifinalist)

One foreign player was seeded.

  1. Argentina Mary Terán de Weiss (Second round)

Draw

Final Eight

  Quarterfinals Semifinals Finals
                                       
  2  United States Sarah Palfrey Cooke 6 6  
7  United States Dorothy Bundy 3 4  
  2  United States Sarah Palfrey Cooke 6 6  
  4  United States Louise Brough 3 4  
4  United States Louise Brough 6 6
  5  United States Patricia Todd 2 4  
    2  United States Sarah Palfrey Cooke 3 8 6
  1  United States Pauline Betz 6 6 4
  1  United States Pauline Betz 0 6 6  
6  United States Mary Arnold 6 4 4  
  1  United States Pauline Betz 6 6
  8  United States Doris Hart 3 2  
3  United States Margaret Osborne 2 3  
  8  United States Doris Hart 6 6  

References

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