1948 U.S. National Championships – Women's Singles

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Women's Singles
1948 U.S. National Championships
Champion United States Margaret Osborne duPont[1]
Runner-up United States Louise Brough
Final score 4–6, 6–4, 15–13
Events
Singles men women
Doubles men women

Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the Women's Singles tennis title at the 1948 U.S. National Championships.[1][2]

Seeds

The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]


  1. United States Louise Brough (Finalist)
  2. United States Doris Hart (Quarterfinalist)
  3. United States Margaret Osborne duPont (Champion)
  4. United States Pat Canning Todd (Semifinalist)
  5. United States Shirley Fry (Third round)
  6. United States Beverly Baker (Quarterfinalist)
  7. United States Gussy Moran (Semifinalist)

Draw

Key

  • Q = Qualifier
  • WC = Wild Card
  • LL = Lucky Loser
  • r. = retired

Final Eight

  Quarterfinals Semifinals Finals
                                       
  7  United States Gussy Moran 6 6  
2  United States Doris Hart 4 4  
  7  United States Gussy Moran 8 4  
  3  United States Margaret Osborne duPont 10 6  
3  United States Margaret Osborne duPont 1 6 6
   United States Beverly Baker 6 2 0  
    3  United States Margaret Osborne duPont 4 6 15
  1  United States Louise Brough 6 4 13
  1  United States Louise Brough 6 6  
 United States Virginia Kovacs 3 2  
  1  United States Louise Brough 6 6
  4  United States Pat Canning Todd 3 3  
4  United States Pat Canning Todd 6 6  
   United States Madge Vosters 3 1  

References

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