Belgian general election, 1886
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69 of the 138 seats in the Chamber of Representatives 70 seats needed for a majority |
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Partial general elections were held in Belgium on 8 June 1886.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 98 of the 138 seats.[2]
Under the alternating system, elections were only held in four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders.
Results
Chamber of Representatives
| Party | Votes | % | Seats | ||
|---|---|---|---|---|---|
| Won | Total | +/– | |||
| Liberal Party | 18,965 | 51.3 | 37 | 40 | –12 |
| Catholic Party | 17,979 | 48.7 | 32 | 98 | +12 |
| Invalid/blank votes | – | – | – | – | |
| Total | 36,944 | 100 | 69 | 138 | 0 |
| Registered voters/turnout | 57,962 | – | – | – | |
| Source: Mackie & Rose,[3] Sternberger et al | |||||
