Belgian general election, 1888
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69 of the 138 seats in the Chamber of Representatives 70 seats needed for a majority |
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Partial general elections were held in Belgium on 12 June 1888.[1][2] The result was a victory for the Catholic Party, which won 98 of the 138 seats in the Chamber of Representatives and 47 of the 69 seats in the Senate.[2]
Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.
Results
Chamber of Representatives
| Party | Votes | % | Seats | ||
|---|---|---|---|---|---|
| Won | Total | +/– | |||
| Catholic Party | 31,273 | 58.4 | 66 | 98 | 0 |
| Liberal Party | 19,967 | 37.3 | 3 | 40 | 0 |
| Others | 2,277 | 4.3 | 0 | 0 | New |
| Invalid/blank votes | – | – | – | – | |
| Total | 53,517 | 100 | 69 | 138 | 0 |
| Registered voters/turnout | 73,276 | – | – | – | |
| Source: Mackie & Rose,[3] Sternberger et al | |||||
Senate
| Party | Votes | % | Seats |
|---|---|---|---|
| Catholic Party | 47 | ||
| Liberal Party | 18 | ||
| Independents | 4 | ||
| Total | 69 | ||
| Source: Sternberger et al. | |||
