Belgian general election, 1896
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77 of the 152 seats in the Chamber of Representatives |
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Partial legislative elections were held in Belgium on 5 and 12 July 1896.[1] Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders. Thus, only 77 seats out of the 152 seats in the Chamber of Representatives were up for election. The Catholic Party retained their absolute majority.[2]
The Liberal Party, who lost two-thirds of their seats in the previous elections, saw their number of seats decrease further.
Results
| Party | Votes | % | Seats | +/– |
|---|---|---|---|---|
| Catholic Party | 492,541 | 49.7 | 111 | +7 |
| Liberal Party | 193,563 | 19.5 | 13 | –7 |
| Belgian Labour Party | 150,260 | 15.2 | 28 | 0 |
| Christene Volkspartij | 73,077 | 7.4 | 0 | 0 |
| Liberal-Socialist Cartels | 49,614 | 5.0 | 0 | 0 |
| Other parties | 32,317 | 3.3 | 0 | 0 |
| Invalid/blank votes | – | – | – | |
| Total | 991,372 | 100 | 152 | 0 |
| Source: Nohlen & Stöver | ||||
