Hobart Township, Lake County, Indiana
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Hobart Township | |
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Township | |
Coordinates: Lua error in package.lua at line 80: module 'strict' not found. | |
Country | United States |
State | Indiana |
County | Lake |
Government | |
• Type | Indiana township |
Area | |
• Total | 25.98 sq mi (67.3 km2) |
• Land | 25.47 sq mi (66.0 km2) |
• Water | 0.51 sq mi (1.3 km2) |
Elevation[1] | 627 ft (191 m) |
Population (2010) | |
• Total | 39,417 |
• Density | 1,547.4/sq mi (597.5/km2) |
FIPS code | 18-34132[2] |
GNIS feature ID | 453414 |
Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.[3]
Geography
According to the 2010 census, the township has a total area of 25.98 square miles (67.3 km2), of which 25.47 square miles (66.0 km2) (or 98.04%) is land and 0.51 square miles (1.3 km2) (or 1.96%) is water.[3]
References
- ↑ Lua error in package.lua at line 80: module 'strict' not found.
- ↑ Lua error in package.lua at line 80: module 'strict' not found.
- ↑ 3.0 3.1 Lua error in package.lua at line 80: module 'strict' not found.
External links
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