United States presidential election in Maine, 1940

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United States presidential election in Maine, 1940

← 1936 November 5, 1940 1944 →
  WendellWillkie.png FDRoosevelt1938.png
Nominee Wendell Willkie Franklin D. Roosevelt
Party Republican Democratic
Home state Indiana New York
Running mate Charles L. McNary Henry A. Wallace
Electoral vote 5 0
Popular vote 163,951 156,478
Percentage 51.10% 48.77%

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Maine took place on November 5, 1940. All contemporary 48 states were part of the 1940 United States presidential election. State voters chose five electors to the Electoral College, which selected the President and Vice President.

Maine was won by Republican businessman Wendell Willkie of Indiana, who was running against incumbent Democratic President Franklin D. Roosevelt of New York. Willkie ran with Senator Charles L. McNary of Oregon while Roosevelt ran with Henry A. Wallace of Iowa.

Willkie won Maine by a narrow margin of 2.33 percent.

Results

United States presidential election in Maine, 1940[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Wendell Willkie of Indiana Charles Linza McNary of Oregon 163,951 51.10% 5 100.00%
Democratic Franklin Delano Roosevelt of New York Henry Agard Wallace of Iowa 156,478 48.77% 0 0.00%
Communist Earl Russell Browder of Kansas James W. Ford of New York 411 0.13% 0 0.00%
Total 320,840 100.00% 5 100.00%


References

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