United States presidential election in Michigan, 1852

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United States presidential election in Michigan, 1852

← 1848 November 2, 1852 1856 →
  Mathew Brady - Franklin Pierce - alternate crop.jpg Winfield Scott by Fredricks, 1862.jpg JP-Hale.jpg
Nominee Franklin Pierce Winfield Scott John P. Hale
Party Democratic Whig Free Soil
Home state New Hampshire New Jersey New Hampshire
Running mate William R. King William A. Graham George W. Julian
Electoral vote 6 0 0
Popular vote 41,842 33,860 7,237
Percentage 50.45% 40.83% 8.73%

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Michigan took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Michigan voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott and Free Soil candidate John P. Hale. Pierce won Michigan by a margin of 9.62%.

Results

United States presidential election in Michigan, 1852[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 41,842 50.45% 6 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 33,860 40.83% 0 0.00%
Free Soil John P. Hale of New Hampshire George W. Julian of Indiana 7,237 8.73% 0 0.00%
Total 82,939 100.00% 6 100.00%

References

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