United States presidential election in New Jersey, 1884

Main article: United States presidential election, 1884

United States presidential election in New Jersey, 1884

November 4, 1884

Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 9 0 Popular vote 127,798 123,440 Percentage 48.98% 47.31%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

The 1884 United States presidential election in New Jersey took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won his birth state by a very narrow margin of 1.67%.

Results

United States presidential election in New Jersey, 1884
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	127,798	48.98%	9	100.00%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	123,440	47.31%	0	0.00%
	Prohibition	John Pierce St. John of Kansas	William Daniel of Maryland	6,159	2.36%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	3,496	1.34%	0	0.00%
	N/A	Others	Others	28	0.01%	0	0.00%
Total				260,921	100.00%	9	100.00%