United States presidential election in New York, 1836

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Main article: United States presidential election, 1836

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The 1836 United States presidential election in New York took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose forty-two representatives, or electors to the Electoral College, who voted for President and Vice President.

New York voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New York by a margin of 9.26%.

Results

United States presidential election in New York, 1836[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 166,795 54.63% 42 100.00%
Whig William Henry Harrison of Ohio Francis Granger of New York 138,548 45.37% 0 0.00%
Total 305,343 100.00% 42 100.00%

References

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