United States presidential election in Rhode Island, 1844

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Main article: United States presidential election, 1844

Lua error in package.lua at line 80: module 'strict' not found. The 1844 United States presidential election in Rhode Island took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Rhode Island voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Rhode Island by a margin of 19.97%.

Results

United States presidential election in Rhode Island, 1844[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig Henry Clay of Kentucky Theodore Frelinghuysen of New York 7,322 59.55% 4 100.00%
Democratic James K. Polk of Tennessee George M. Dallas of Pennsylvania 4,867 39.58% 0 0.00%
Liberty James G. Birney of Michigan Thomas Morris of Ohio 107 0.87% 0 0.00%
Total 12,296 100.00% 4 100.00%

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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