United States presidential election in Rhode Island, 1960

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United States presidential election in Rhode Island, 1960

← 1956 November 8, 1960 1964 →
  John F. Kennedy, White House color photo portrait.jpg VP-Nixon.png
Nominee John F. Kennedy Richard Nixon
Party Democratic Republican
Home state Massachusetts California
Running mate Lyndon B. Johnson Henry Cabot Lodge, Jr.
Electoral vote 4 0
Popular vote 258,032 147,502
Percentage 63.63% 36.36%

President before election

Dwight Eisenhower
Republican

Elected President

John F. Kennedy
Democratic

Lua error in package.lua at line 80: module 'strict' not found. The 1960 United States presidential election in Connecticut took place on November 8, 1960 as part of the 1960 United States presidential election, which was held throughout all 50 states. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Democratic nominee, Senator John F. Kennedy of Massachusetts, over the Republican nominee, Vice President Richard Nixon of California. Kennedy ran with Senate Majority Leader Lyndon B. Johnson of Texas, while Nixon's running mate was Ambassador Henry Cabot Lodge, Jr. of Massachusetts.

Kennedy carried Rhode Island by a narrow margin of 27.27 percent.

Results

United States presidential election in Rhode Island, 1960[1]
Party Candidate Votes Percentage Electoral votes
Democratic John F. Kennedy 258,032 63.63% 4
Republican Richard Nixon 147,502 36.36% 0
Write-ins Write-ins 1 0.01% 0
Totals 405,535 100.00% 4


References

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