Algebraic interior

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In functional analysis, a branch of mathematics, the algebraic interior or radial kernel of a subset of a vector space is a refinement of the concept of the interior. It is the subset of points contained in a given set with respect to which it is absorbing, i.e. the radial points of the set.[1] The elements of the algebraic interior are often referred to as internal points.[2][3]

Formally, if X is a linear space then the algebraic interior of A \subseteq X is

\operatorname{core}(A) := \left\{x_0 \in A: \forall x \in X, \exists t_x > 0, \forall t \in [0,t_x], x_0 + tx \in A\right\}.[4]

Note that in general \operatorname{core}(A) \neq \operatorname{core}(\operatorname{core}(A)), but if A is a convex set then \operatorname{core}(A) = \operatorname{core}(\operatorname{core}(A)). If A is a convex set then if x_0 \in \operatorname{core}(A), y \in A, 0 < \lambda \leq 1 then \lambda x_0 + (1 - \lambda)y \in \operatorname{core}(A).

Example

If A \subset \mathbb{R}^2 such that A = \{x \in \mathbb{R}^2: x_2 \geq x_1^2 \text{ or } x_2 \leq 0\} then 0 \in \operatorname{core}(A), but 0 \not\in \operatorname{int}(A) and 0 \not\in \operatorname{core}(\operatorname{core}(A)).

Properties

Let A,B \subset X then:

Relation to interior

Let X be a topological vector space, \operatorname{int} denote the interior operator, and A \subset X then:

  • \operatorname{int}A \subseteq \operatorname{core}A
  • If A is nonempty convex and X is finite-dimensional, then \operatorname{int}A = \operatorname{core}A[2]
  • If A is convex with non-empty interior, then \operatorname{int}A = \operatorname{core}A[6]
  • If A is a closed convex set and X is a complete metric space, then \operatorname{int}A = \operatorname{core}A[7]

See also

References

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