1997 Fed Cup Americas Zone Group I – Knockout Stage
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The Knockout Stage of the 1997 Fed Cup Americas Zone Group I was the final stage of the Zonal Competition involving teams from the Americas. Those that qualified for this stage placed first and second in their respective pools.
Placing | Pool A | Pool B |
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3 | ![]() |
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4 | ![]() |
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5 | ![]() |
The four teams were then randomly drawn into a two-stage knockout tournament, with the winner advancing to the World Group II Play-offs.
Contents
Draw
Semifinals 3 May |
Final 4 May |
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3 |
Semifinals
Canada vs. Peru
![]() Canada 3 |
Club Palestino, Santiago, Chile 3 May 1997 Red clay (outdoors) |
![]() Peru 0 |
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Brazil vs. Colombia
![]() Brazil 0 |
Club Palestino, Santiago, Chile 3 May 1997 Red clay (outdoors) |
![]() Colombia 3 |
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Final
Canada vs. Colombia
![]() Canada 2 |
Club Palestino, Santiago, Chile 4 May 1997 Red clay (outdoors) |
![]() Colombia 1 |
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Canada advanced to the World Group II Play-offs, where they were drawn against
Slovakia. However, they lost 0–5, and thus returned to the Americas Zone Group I in 1997.[4]