2006 ATP Buenos Aires – Doubles

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Doubles
2006 ATP Buenos Aires
Champions Czech Republic František Čermák
Czech Republic Leoš Friedl
Runners-up Greece Vasilis Mazarakis
Serbia and Montenegro Boris Pašanski
Final score 6–1, 6–2
Events
Singles Doubles

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František Čermák and Leoš Friedl were the defending champions.

Čermák and Friedl successfully defended their title, defeating Vasilis Mazarakis and Boris Pašanski 6–1, 6–2 in the final.

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 Czech Republic F Čermák
Czech Republic L Friedl
6 6  
  Czech Republic D Škoch
Czech Republic J Vaněk
1 2   1 Czech Republic F Čermák
Czech Republic L Friedl
6 5 [11]
  Spain A Montañés
Spain A Portas
3 0     Argentina C Berlocq
Italy P Starace
2 7 [9]
  Argentina C Berlocq
Italy P Starace
6 6   1 Czech Republic F Čermák
Czech Republic L Friedl
5 6 [11]
3 Argentina M García
Argentina S Prieto
6 6     Spain A Martín
Spain F Vicente
7 3 [9]
  Spain N Almagro
Czech Republic T Cibulec
3 1   3 Argentina M García
Argentina S Prieto
5 64  
WC Argentina JM del Potro
Argentina J Mónaco
3 6 [7]   Spain A Martín
Spain F Vicente
7 77  
  Spain A Martín
Spain F Vicente
6 3 [10] 1 Czech Republic F Čermák
Czech Republic L Friedl
6 6  
WC Argentina Emiliano Masso
Argentina L Mayer
2 6 [5]   Greece V Mazarakis
Serbia and Montenegro B Pašanski
1 2  
  France O Patience
France F Serra
6 2 [10]   France O Patience
France F Serra
     
  Italy A di Mauro
Italy F Volandri
2 3   4 Argentina A Calleri
Argentina G Etlis
w/o    
4 Argentina A Calleri
Argentina G Etlis
6 6   4 Argentina A Calleri
Argentina G Etlis
     
  Brazil M Daniel
Brazil F Saretta
62 6 [8]   Greece V Mazarakis
Serbia and Montenegro B Pašanski
w/o    
  Greece V Mazarakis
Serbia and Montenegro B Pašanski
77 1 [10]   Greece V Mazarakis
Serbia and Montenegro B Pašanski
4 6 [12]
  Spain JC Ferrero
Spain S Ventura
6 6     Spain JC Ferrero
Spain S Ventura
6 4 [10]
2 Poland M Fyrstenberg
Poland M Matkowski
4 3  

References