Belgian general election, 1868
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63 of the 122 seats in the Chamber of Representatives 62 seats needed for a majority |
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General elections were held in Belgium on 9 June 1868.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Liberal Party, which won 72 of the 122 seats.[2] Voter turnout was 55.6%, although only 55,297 people were eligible to vote.
Under the alternating system, elections were only held in five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders. A special election was held in the arrondissement of Tongeren.
Results
Chamber of Representatives
| Party | Votes | % | Seats | ||
|---|---|---|---|---|---|
| Won | Total | +/– | |||
| Catholics | 16,918 | 55.1 | 33 | 50 | –2 |
| Liberal Party | 13,619 | 44.3 | 30 | 72 | +2 |
| Others | 184 | 0.6 | 0 | 0 | New |
| Invalid/blank votes | 3,358 | – | – | – | – |
| Total | 34,079 | 100 | 63 | 122 | 0 |
| Registered voters/turnout | 55,297 | 55.6 | – | – | – |
| Source: Mackie & Rose,[3] Sternberger et al | |||||
