United States presidential election in New York, 1860
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Lua error in package.lua at line 80: module 'strict' not found. The 1860 United States presidential election in New York took place on November 6, 1860 throughout all 33 states which was part of the 1860 United States presidential election. Voters chose 35 electors of the Electoral College, who voted for President and Vice President.
New York was won by Republican candidate Abraham Lincoln, who defeated Democratic presidential candidate Stephen A. Douglas by a narrow margin of 7.42%.
Results
| United States presidential election in New York, 1860[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 362,646 | 53.71% | 35 | 100.00% | ||
| Democratic | Stephen A. Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 312,510 | 46.29% | 0 | 0.00% | ||
| Total | 675,156 | 100.00% | 35 | 100.00% | ||||
References
- ↑ Lua error in package.lua at line 80: module 'strict' not found.
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