United States presidential election in Connecticut, 1940

Main article: United States presidential election, 1940

United States presidential election in Connecticut, 1940

November 5, 1940

Nominee Franklin D. Roosevelt Wendell Willkie Party Democratic Republican Home state New York Indiana Running mate Henry A. Wallace Charles L. McNary Electoral vote 8 0 Popular vote 417,621 361,819 Percentage 53.44% 46.30%

President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

The 1940 United States presidential election in Connecticut took place on November 5, 1940. All contemporary 48 states were part of the 1940 United States presidential election. State voters chose eight electors to the Electoral College, which selected the President and Vice President.

Connecticut was won by incumbent Democratic President Franklin D. Roosevelt of New York, who was running against Republican businessman Wendell Willkie of Indiana. Roosevelt ran with Henry A. Wallace of Iowa as his running mate, and Willkie ran with Senator Charles L. McNary of Oregon.

Roosevelt won Connecticut by a narrow margin of 7.14 percent.

Results

United States presidential election in Connecticut, 1940
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Franklin Delano Roosevelt of New York	Henry Agard Wallace of Iowa	417,621	53.44%	8	100.00%
	Republican	Wendell Willkie of Indiana	Charles Linza McNary of Oregon	361,819	46.30%	0	0.00%
	Communist	Earl Russell Browder of Kansas	James W. Ford of New York	1,091	0.14%	0	0.00%
	Socialist Labor	John W. Aiken of Connecticut	Aaron M. Orange of New York	971	0.12%	0	0.00%
Total				781,502	100.00%	8	100.00%