United States presidential election in Indiana, 1940
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All 14 Indiana votes to the Electoral College |
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The 1940 United States presidential election in Indiana took place on November 5, 1940, as part of the 1940 United States presidential election. Indiana voters chose fourteen[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Indiana was won by Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 50.45% of the popular vote, against incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 49.03% of the popular vote.[3][4]
Results
| United States presidential election in Indiana, 1940 | ||||
|---|---|---|---|---|
| Party | Candidate | Votes | % | |
| Republican | Wendell Willkie | 899,466 | 50.45% | |
| Democratic | Franklin D. Roosevelt (inc.) | 874,063 | 49.03% | |
| Prohibition | Roger Babson | 6,437 | 0.36% | |
| Write-in | 2,781 | 0.16% | ||
| Total votes | 1,782,747 | 100% | ||
References
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| General articles |
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| Local results |
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| Other 1940 elections |
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